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- https://bio.libretexts.org/LibreTexts/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_(Facciotti)/Readings/2017_SUMMER_SESSION_1/2017_SS1_Lecture_14Due to the structural arrangement of the DNA at the midpoint this means that as the new double strands are formed, each origin point moves away from the cell wall attachment toward the opposite ends o...Due to the structural arrangement of the DNA at the midpoint this means that as the new double strands are formed, each origin point moves away from the cell wall attachment toward the opposite ends of the cell. Because the separation of the sister chromatids during anaphase is an irreversible step, the cycle will not proceed until the kinetochores of each pair of sister chromatids are firmly anchored to spindle fibers arising from opposite poles of the cell.
- https://bio.libretexts.org/LibreTexts/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_(Facciotti)/Readings/W2017_Readings/W2017_Lecture_17_reading
- https://bio.libretexts.org/LibreTexts/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_(Facciotti)/Readings/2017_SUMMER_SESSION_1/2017_SS1_Lecture_13The CEC binds to the RNA polymerase very early in transcription and carries out a modification of the 5' triphosphate, the subsequent transfer of at GTP to this end (connecting the two nucleotides usi...The CEC binds to the RNA polymerase very early in transcription and carries out a modification of the 5' triphosphate, the subsequent transfer of at GTP to this end (connecting the two nucleotides using a unique 5'-to-5' linkage), the methylation of the newly transferred guanine, and in some transcripts the additional modifications to the first few nucleotides.
- https://bio.libretexts.org/LibreTexts/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_(Facciotti)/Readings/W2017_Readings/W2017_Lecture_12_readingIf we examine the reaction from the standpoint of the products and reactants and ask "how can we recombine atoms and bonds in the reactants to get the products?", we find that a phosphoanhydride bond ...If we examine the reaction from the standpoint of the products and reactants and ask "how can we recombine atoms and bonds in the reactants to get the products?", we find that a phosphoanhydride bond between an oxygen and a phosphorus must be broken in the ATP, a bond between an oxygen and hydrogen broken in the water, a bond made between the OH (that came from the splitting of water) and the phosphorus (from the freed PO3-2), and a bond must be formed between the H (derived from the splitting …
- https://bio.libretexts.org/Courses/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_-_Molecules_to_Cell/16%3A_Winter_2024_Bis2A_Facciotti/16.13%3A_Winter_2024_Bis2A_Facciotti_Reading_09The models of the proteins should include annotation/shading or other way of indicating the types of amino acid functional groups you might expect to see in (a) the exterior of the protein in contact ...The models of the proteins should include annotation/shading or other way of indicating the types of amino acid functional groups you might expect to see in (a) the exterior of the protein in contact with the lipid bilayer, (b) the regions of the exterior part of the protein that interact with the lipid polar groups, and (c) some attempt to illustrate the types of residues one might expect to find in the core of the protein depending on substrate being transported.
- https://bio.libretexts.org/Courses/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_-_Molecules_to_Cell/17%3A_Spring_2024_Bis2A_Namekawa_Igo/17.64%3A_Winter_2024_Bis2A_Facciotti_Reading_11The difference in the reduction potential for the reaction (∆E 0 ’), can be calculated by taking the difference between the E 0 ’ for the oxidant (the compound getting the electrons and causing the ox...The difference in the reduction potential for the reaction (∆E 0 ’), can be calculated by taking the difference between the E 0 ’ for the oxidant (the compound getting the electrons and causing the oxidation of the other compound) and the reductant (the compound losing the electrons).
- https://bio.libretexts.org/Courses/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_-_Molecules_to_Cell/16%3A_Winter_2024_Bis2A_Facciotti/16.23%3A_Winter_2024_Bis2A_Facciotti_Reading_19Because DNA polymerase can add nucleotides in only one direction (5' to 3'), the leading strand allows for continuous synthesis until the end of the chromosome is reached; however, as the replication ...Because DNA polymerase can add nucleotides in only one direction (5' to 3'), the leading strand allows for continuous synthesis until the end of the chromosome is reached; however, as the replication complex arrives at the end of the lagging strand there is no place for the primase to "land" and synthesize an RNA primer so that the synthesis of the missing lagging strand DNA fragment at the end of the chromosome can be initiated by the DNA polymerase.
- https://bio.libretexts.org/LibreTexts/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_(Facciotti)/Readings/2017_SUMMER_SESSION_1/2017_SS1_Lecture_12In the examples above, the binding of a effector molecule to a transcription factor could have one of two different effects: (1) binding of the effector molecule could induce a DNA-bound transcription...In the examples above, the binding of a effector molecule to a transcription factor could have one of two different effects: (1) binding of the effector molecule could induce a DNA-bound transcription factor to release from its binding site, derepressing a promoter, and "turning on" gene expression. (2) binding of the effector molecule to the transcription factor could induce the TF to bind to its DNA binding site, repressing transcription and "turning off" gene expression.
- https://bio.libretexts.org/Courses/Wheaton_College_Massachusetts/Principles_of_Biochemistry/08%3A_Carbohydrate_structure_and_metabolism/8.01%3A_Carbohydrates_overviewThe chemical formula for glucose and galactose is C 6 H 12 O 6 ; both are hexoses, but the arrangements of the hydrogens and hydroxyl groups are different at position C 4 . Because of this small diffe...The chemical formula for glucose and galactose is C 6 H 12 O 6 ; both are hexoses, but the arrangements of the hydrogens and hydroxyl groups are different at position C 4 . Because of this small difference, they differ structurally and chemically and are known as chemical isomers because of the different arrangement of functional groups around the asymmetric carbon; both
- https://bio.libretexts.org/Courses/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_-_Molecules_to_Cell/BIS_2A%3A_Introductory_Biology_-_Essentials_of_Life_on_Earth_(Facciotti)/01%3A_Modules/1.13%3A_Winter_2025_Bis2A_Facciotti_Reading_13Follow energy from "sources" of electrons with relatively low reduction potentials to "sinks" with higher redox potentials, describe the major transfers of energy and how this energy is "stored" at ea...Follow energy from "sources" of electrons with relatively low reduction potentials to "sinks" with higher redox potentials, describe the major transfers of energy and how this energy is "stored" at each stage.; ME.14 Given metabolic maps of glycolysis and TCA cycle, follow the flow of electrons from energy source to mobile carrier NADH and use a provided redox tower to quantitatively describe the energy transformations.; ME.10 Explain the central role of Acetyl CoA in carbon metabolism includin…
- https://bio.libretexts.org/Courses/University_of_California_Davis/BIS_2A%3A_Introductory_Biology_-_Molecules_to_Cell/BIS_2A%3A_Introductory_Biology_-_Essentials_of_Life_on_Earth_(Facciotti)/01%3A_Modules/1.02%3A_Winter_2025_Bis2A_Facciotti_Reading_02Note how the dipoles of the water molecules surrounding the ions are aligned such that complementary charges/partial charges are associating with one another (i.e., the partial positive charges on the...Note how the dipoles of the water molecules surrounding the ions are aligned such that complementary charges/partial charges are associating with one another (i.e., the partial positive charges on the water molecules align with the negative chloride ion whereas the partial negative charges on the oxygen of water align with the positively charged sodium ion).
