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13.6: Gene Regulation - Inducible Operon

  • Page ID
    159996
    • Ying Liu, Serena Chang, Grace Murphy, Esther Ajayi-Akinsulire, Isobel Ardren, Izabella Guy, Kai Johnston, Saskia Lee, and Lauren Russell
    • City College of San Francisco

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    Learning Objectives
    • Describe the structure and components of the lac operon
    • Differentiate between positive and negative regulation of the lac operon
    • Identify the conditions under which the lac operon is activated or repressed

    The lac Operon: An Inducible Operon

    The lac operon is an example of an inducible operon that is also subject to activation in the absence of glucose (Figure \(\PageIndex{3}\)). The lac operon encodes three structural genes necessary to acquire and process the disaccharide lactose from the environment, breaking it down into the simple sugars glucose and galactose. For the lac operon to be expressed, lactose must be present. This makes sense for the cell because it would be energetically wasteful to create the enzymes to process lactose if lactose was not available.

    In the absence of lactose, the lac repressor is bound to the operator region of the lac operon, physically preventing RNA polymerase from transcribing the structural genes. However, when lactose is present, the lactose inside the cell is converted to allolactose. Allolactose serves as an inducer molecule, binding to the repressor and changing its shape so that it is no longer able to bind to the operator DNA. Removal of the repressor in the presence of lactose allows RNA polymerase to move through the operator region and begin transcription of the lac structural genes.

    A diagram of the lac operon. The top image shows what occurs in the absence of lactose. In the absence of lactose, the lac repressor binds the operator and transcription is blocked. The repressor is not bound to lactose but is bound to the operator. RNA polymerase is bound to the promoter but is blocked from transcription by the repressor. The bottom image shows the presence of lactose. In the presence of lactose, the lac repressor is released from the operator and transcription proceeds at a slow rate. The image shows lactose bound to the repressor which is no longer bound to the operator. RNA polymerase is bound to the promoter and an arrow indicates that transcription is occurring.
    Figure \(\PageIndex{3}\): The three structural genes that are needed to degrade lactose in E. coli are located next to each other in the lac operon. When lactose is absent, the repressor protein binds to the operator, physically blocking the RNA polymerase from transcribing the lac structural genes. When lactose is available, a lactose molecule binds the repressor protein, preventing the repressor from binding to the operator sequence, and the genes are transcribed.

    Query \(\PageIndex{1}\)

    Query \(\PageIndex{1}\)

    The lac Operon: Activation by Catabolite Activator Protein

    Bacteria typically have the ability to use a variety of substrates as carbon sources. However, because glucose is usually preferable to other substrates, bacteria have mechanisms to ensure that alternative substrates are only used when glucose has been depleted. Additionally, bacteria have mechanisms to ensure that the genes encoding enzymes for using alternative substrates are expressed only when the alternative substrate is available. In the 1940s, Jacques Monod was the first to demonstrate the preference for certain substrates over others through his studies of E. coli’s growth when cultured in the presence of two different substrates simultaneously. Such studies generated diauxic growth curves, like the one shown in Figure \(\PageIndex{4}\). Although the preferred substrate glucose is used first, E. coli grows quickly and the enzymes for lactose metabolism are absent. However, once glucose levels are depleted, growth rates slow, inducing the expression of the enzymes needed for the metabolism of the second substrate, lactose. Notice how the growth rate in lactose is slower, as indicated by the lower steepness of the growth curve.

    The ability to switch from glucose use to another substrate like lactose is a consequence of the activity of an enzyme called Enzyme IIA (EIIA). When glucose levels drop, cells produce less ATP from catabolism (see Catabolism of Carbohydrates), and EIIA becomes phosphorylated. Phosphorylated EIIA activates adenylyl cyclase, an enzyme that converts some of the remaining ATP to cyclic AMP (cAMP), a cyclic derivative of AMP and important signaling molecule involved in glucose and energy metabolism in E. coli. As a result, cAMP levels begin to rise in the cell (Figure \(\PageIndex{5}\)).

    The lac operon also plays a role in this switch from using glucose to using lactose. When glucose is scarce, the accumulating cAMP caused by increased adenylyl cyclase activity binds to catabolite activator protein (CAP), also known as cAMP receptor protein (CRP). The complex binds to the promoter region of the lac operon (Figure \(\PageIndex{6}\)). In the regulatory regions of these operons, a CAP binding site is located upstream of the RNA polymerase binding site in the promoter. Binding of the CAP-cAMP complex to this site increases the binding ability of RNA polymerase to the promoter region to initiate the transcription of the structural genes. Thus, in the case of the lac operon, for transcription to occur, lactose must be present (removing the lac repressor protein) and glucose levels must be depleted (allowing binding of an activating protein). When glucose levels are high, there is catabolite repression of operons encoding enzymes for the metabolism of alternative substrates. Because of low cAMP levels under these conditions, there is an insufficient amount of the CAP-cAMP complex to activate transcription of these operons. See Table \(\PageIndex{1}\) for a summary of the regulation of the lac operon.

    Graph with time (hours) on the X axis and Log of E. coli cells on the Y axis. For the first hour the graph is relatively flat but then becomes quite steep for the next 3 hours. The graph increases from 0.3 to 1 in 3 hours. This part of the graph is labeled E. coli uses glucose. The next part of the graph begins with another flat region of about an hout and then there is another increase. This increase goes from 1.2 to 1.9 in 4 hours. This part of the graph is labeled E. coli uses lactose.
    Figure \(\PageIndex{4}\): When grown in the presence of two substrates, E. coli uses the preferred substrate (in this case glucose) until it is depleted. Then, enzymes needed for the metabolism of the second substrate are expressed and growth resumes, although at a slower rate.
    ATP contains 3 phosphate groups. Adenylyl cyclase removes two of these phosphate groups. The remaining phosphate group is linked into the sugar to make cAMP. Cyclic AMP is made of a ribose sugar with oxygens at both carbons 2 and 3 (the carbons at the bottom of the pentagon). The oxygen bound to carbon 3 is also bound to the phosphorus. Similarly, the oxygen bound at carbon 5 was already bound to the phosphorus. This forms a ring where the phosphorus is linked with an oxygen to both carbons 3 and 5.
    Figure \(\PageIndex{5}\): When ATP levels decrease due to depletion of glucose, some remaining ATP is converted to cAMP by adenylyl cyclase. Thus, increased cAMP levels signal glucose depletion.
    Diagram of the lac operon with and without cAMP. A) In the absence of cAMP, CAP does not bind the promoter. RNA polymerase does bind to the promoter and transcription occurs at a low rate. In the presence of cAMP, CAP binds the promoter and increases RNA polymerase activity. This is shown with a circle labeled cAMP + CAP bound to the promoter. RNA polymerase is also bound to the promoter and a thick arrow indicates faster transcription. B) cAMO-CAP complex stimulates RNA polymerase activity and increases RNA synthesis. However, even in the presence of cAMP-CAP complex, RNA synthesis is blocked when repressor is bound ot he operator. This is shows as the cAMP + CAP circle as well as the RNA polymerase bound to the promoter. The repressor is bound to the operator and this blocks RNA polymerase from moving forward.
    Figure \(\PageIndex{6}\): (a) In the presence of cAMP, CAP binds to the promoters of operons, like the lac operon, that encode genes for enzymes for the use of alternate substrates. (b) For the lac operon to be expressed, there must be activation by cAMP-CAP as well as removal of the lac repressor from the operator.
    Table \(\PageIndex{1}\): Conditions Affecting Transcription of the lac Operon
    Glucose CAP binds Lactose Repressor binds Transcription
    + + No
    + + Some
    + + No
    + + Yes
    Link to Learning

    Watch an animated tutorial about the workings of lac operon here.

    Query \(\PageIndex{1}\)

    Query \(\PageIndex{1}\)

    Key Concepts and Summary

    • The lac operon is a classic example an inducible operon. When lactose is present in the cell, it is converted to allolactose. Allolactose acts as an inducer, binding to the repressor and preventing the repressor from binding to the operator. This allows transcription of the structural genes.
    • The lac operon is also subject to activation. When glucose levels are depleted, some cellular ATP is converted into cAMP, which binds to the catabolite activator protein (CAP). The cAMP-CAP complex activates transcription of the lac operon. When glucose levels are high, its presence prevents transcription of the lac operon and other operons by catabolite repression.

    This page titled 13.6: Gene Regulation - Inducible Operon is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Ying Liu, Serena Chang, Grace Murphy, Esther Ajayi-Akinsulire, Isobel Ardren, Izabella Guy, Kai Johnston, Saskia Lee, and Lauren Russell via source content that was edited to the style and standards of the LibreTexts platform.